x^2+240x-9600=0

Solution for x^2+240x-9600=0 equation:

x^2+240x-9600=0

a = 1; b = 240; c = -9600;
Δ = b2-4ac
Δ = 2402-4·1·(-9600)
Δ = 96000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96000}=\sqrt{6400*15}=\sqrt{6400}*\sqrt{15}=80\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-80\sqrt{15}}{2*1}=\frac{-240-80\sqrt{15}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+80\sqrt{15}}{2*1}=\frac{-240+80\sqrt{15}}{2}
$